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((1.14*10^-3)x)-(1.48*10^-4)=x
We move all terms to the left:
((1.14*10^-3)x)-(1.48*10^-4)-(x)=0
We add all the numbers together, and all the variables
-1x+((1.14*10^-3)x)-0.000148=0
We calculate terms in parentheses: +((1.14*10^-3)x), so:We get rid of parentheses
(1.14*10^-3)x
We multiply parentheses
11.4x^2-3x
Back to the equation:
+(11.4x^2-3x)
11.4x^2-1x-3x-0.000148=0
We add all the numbers together, and all the variables
11.4x^2-4x-0.000148=0
a = 11.4; b = -4; c = -0.000148;
Δ = b2-4ac
Δ = -42-4·11.4·(-0.000148)
Δ = 16.0067488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{16.0067488}}{2*11.4}=\frac{4-\sqrt{16.0067488}}{22.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{16.0067488}}{2*11.4}=\frac{4+\sqrt{16.0067488}}{22.8} $
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